0,5x^2=162

Solution for 0,5x^2=162 equation:

0.5x^2=162

We move all terms to the left:

0.5x^2-(162)=0

a = 0.5; b = 0; c = -162;
Δ = b2-4ac
Δ = 02-4·0.5·(-162)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*0.5}=\frac{-18}{1}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*0.5}=\frac{18}{1}
=18
$